All categories

3 years ago

Please need help please ksjdjdnbdbfhfhfhfjfjfjfjfjfhjfjcjf

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

8 0

$2y = 10x \\ y = 10x \div2 = 5x$
$\frac{ {x}^{2} }{64} - \frac{y^{2} }{36} = 1 \\ \frac{ {x}^{2} }{64} - \frac{(5x)^{2} }{36} = 1 \\ \frac{ {x}^{2} }{64} - \frac{25x^{2} }{36} = 1$
A

You might be interested in

| 2x+5 |>3<br> What is the answer

Sidana [21]

Answer:

If you are solving for X it would be x<-4 or x>-1

Step-by-step explanation:

7 0

3 years ago

The community center has a pottery class each month. Each student pays $15 for the class and $27 for materials. This month the p

Dominik [7]

If you add $15 + $27 because that's how much it costs for each student, you get $42. Then you divide $714 by $42, you get 17 and that's how many students are in the class this month.

3 0

3 years ago

Read 2 more answers

Mikel gave a $1.32 tip for an order that cost $8.80. Determine whether or not each tip below is proportional to Mikel's tip. $2.

ludmilkaskok [199]

Answer:

1. Proportional

2. Not proportional

3. Proportional

Step-by-step explanation:

Mike's proportion

Michael gave $1.32 tip for an order that cost $8.80

$1.32÷$8.80=0.15

Given

1. $2.22 for $14.80

$2.22÷$14.80 =0.15

It is proportional to Mike's tip

2. $1.86 for $10.50

$1.86÷$10.50=0.1771

It I not proportional to Mike's tip

3. $0.78 for $5.20

$0.78÷$5.20=0.15

It is proportional to Mike's tip

Therefore,

1. Proportional

2. Not proportional

3. Proportional

5 0

3 years ago

How can I factorise (2x cubed - 5x + 3) ?

PilotLPTM [1.2K]

$2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}$

$therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}$

7 0

3 years ago

Read 2 more answers

Solve for x. Enter your answer below as an improper fraction in lowest terms,

ICE Princess25 [194]

Answer:

x = $\frac{83}{36}$