Answer:
What are you gonna do is across the x
Step-by-step explanation:
1)
∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰
AB = 370 m
AC = 510 m
To find BC we can use cosine law.
a² = b² + c² -2bc*cos A
|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)
|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =
|BC| ≈ 553 m
2)
To find ∠ACB, we are going to use law of sine.
sin(∠BAC)/|BC| = sin(∠ACB)/|AB|
sin(76⁰)/553 m = sin(∠ACB)/370 m
sin(∠ACB)=(370*sin(76⁰))/553 =0.6492
∠ACB = 40.48⁰≈ 40⁰
3)
∠BAC = 76⁰
∠ACB = 40⁰
∠CBA = 180-(76+40) = 64⁰
Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰
4)
Shortest distance from A to BC is height (h) from A to BC.
We know that area of the triangle
A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).
Also, area the same triangle
A= (1/2)|BC|*h = (1/2)*553*h.
So, we can write
(1/2)*370*510*sin(76⁰) =(1/2)*553*h
370*510*sin(76⁰) =553*h
h= 370*510*sin(76⁰) / 553= 331 m
h=331 m
2
Step-by-step explanation:
-2 -2/ -3+1 = -4/-2 = 2
you just have to use the slope formula
The parent function is y = x^2
There is a compression of 3:
y = 3x^2
There is a shift by 1 unit to the left:
y = 3(x + 1)^2
Answer:
Interior Angle: 165°
Exterior Angle: 15°
Step-by-step explanation:
So first you have to find the sum of all interior angles of a polygon with <u>24 sides</u>. This can be found using the formula:
sum = ( <em>n</em> - 2 ) * 180° where '<em>n</em>' is the number of sides.
When '<em>n</em> = 24' then the sum is:
sum = ( 24 - 2 ) * 180°
Simplify and solve.
sum = 22 * 180°
sum = 3960°
Since there are 24 sides to the polygon, there are 24 interior angles. <u>Assuming that this polygon is equilateral</u>, you can surmise that:
<em>Interior Angle</em> = sum° / <em>n</em> where n is the number of sides,
3960° / 24 = 165° = Interior Angle
Using that information, and combine it with the [Supplementary Angles Theorem] the exterior angle can be found by:
165° + x = 180°
Solve for x.