The area of a rectangle is <em>L x W</em>. We have to get the value of x first so that we can find the area of the rectangle.
To get the value of x
given:
<span>a. 12 & X
b. X-2 & 16 </span>
solution:
12x (x) = (8-2 ) 16
12x = 16x-32
32 = 16x-- 12x
<u>32 </u> = <u>4x</u>
4 4
8 = x
Checking:
a. 12 & X b. X-2 & 16
Area of a rectangle = L x W Area of a rectangle = L x W
=12 x 8 = (8-2) 16
Area of a rectangle = 96 = 6 (16)
Area of a rectangle = 96
Answer:
Step-by-step explanation:
ffffffffff
Answer:
The hyperbolas which open horizontally are:
(x+2)^2/3^2-(2y-10)^2/8^2=1
(x-1)^2/6^2-(2y+6)^2/5^2=1
Step-by-step explanation:
A hyperbola with equation of the form:
(x-h)^2/a^2-(y-k)^2/b^2)=1 opens horizontally
Then, the hyperbolas which open horizontally are:
(x+2)^2/3^2-(2y-10)^2/8^2=1
(x-1)^2/6^2-(2y+6)^2/5^2=1
Slope is 7/3 and y intercept is -3.
The x - intercept of 5x - 3y = 15 is (3, 0)
The y -intercept of 5x - 3y = 15 is (0, -5)
<h3><u>Solution:</u></h3>
Given equation is 5x - 3y = 15
<em><u>To find: x - intercept and y -intercept</u></em>
The x intercept is the point where the line crosses the x axis. At this point y = 0
The y intercept is the point where the line crosses the y axis. At this point x = 0.
<em><u>Finding x - intercept:</u></em>
To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x
So put y = 0 in given equation
5x - 3(0) = 15
5x = 15
x = 3
So the x - intercept is (3, 0)
<em><u>Finding y - intercept:</u></em>
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y
So put x = 0 in given equation
5(0) - 3y = 15
-3y = 15
y = -5
So the y - intercept is (0, -5)
