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zubka84 [21]
3 years ago
9

The y-intercept of the line whose equation is 3x - 2y = 6 is -3 2 6

Mathematics
2 answers:
Ludmilka [50]3 years ago
7 0
The best way to answer this question is to ask yourself what the Y intercept is. The Y intercept is the point on the graph when the line crosses the Y axis. This point will always be wherever X is equal to 0.

So, to find the answer, we need to say that X = 0

3(0) - 2Y = 6

Zero times any number equals zero, so we are left with:

-2Y = 6

Now, we solve for Y by dividing both sides by -2.

Y = 6/(-2)

Y = -3

So, when X = 0, Y = -3.

Thus, the Y intercept is at point (0,-3).
yulyashka [42]3 years ago
4 0

Answer:

The y-intercept is -3

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Julio has $150. Each week, he saves an additional $10.Write a function ()that models the total amount of money Julio has after w
nadya68 [22]

Answer:

The function that models the total amount of money Julio has after weeks is:

f(x)=150+10x, where:

x is the number of weeks

Step-by-step explanation:

With the information provided,  you can say that the total amount of money Julio has would be equal to the initial amount he has plus the result of multiplying the $10 that he saves every week for the number of weeks, which can be expressed as:

f(x)=150+10x, where:

x is the number of weeks

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the price of a discounted skateboard would be 291.84 or if the board was already discounted, the original price was 476.16

Step-by-step explanation:

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Murrr4er [49]

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0.53

Step-by-step explanation:

Basically just go to your calculator and put in 8 divded by 15

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Luke hiked 6 1/4 miles. Joana hiked 2 1/ 5 times as far. how far did joana hike?​
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13.75 or 13 3/4

Step-by-step explanation:

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3 years ago
Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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