11=1/3×6+2 I need help solve and check

Cyber Monday Shopping A survey of U.S. adults found that of people said that they would get no work done on Cyber Monday since t

Delicious77 [7]

Complete question :

Cyber Monday Shopping A survey of 1000 U.S. adults found that 33% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 95% confidence interval of the true proportion.

Answer:

(0.301 ; 0.359)

Step-by-step explanation:

Sample size, n = 1000

Phat = 0.33

(1 - phat) = 1 - 0.33 = 0.67

Zcritical at 95% = 1.96

Confidence interval :

Phat ± margin of error

Margin of Error = Zcritical * sqrt[(phat(1 - phat)) /n]

Margin of Error = 1.96 * sqrt[(0.33 * 0.67) / 1000]

Margin of Error = 1.96 * 0.0148694

Margin of Error = 0.0291440

Lower boundary = (0.33 - 0.0291440) = 0.300856

Upper boundary = (0.33 + 0.0291440) = 0.359144

(0.301 ; 0.359)

3 0

3 years ago

How do i solve this question?

Andrews [41]

when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the resulting function is the same as the original, then is even, if the resulting function is the same as the original but negative, is odd, if neither, well then neither :).

anyway, that said, let's first expand it and then plug in -x,

$\bf f(x)=(x^2-8)^2\implies f(x)=(x^2-8)(x^2-8)\implies f(x)=\stackrel{FOIL}{x^4-16x^2+64}\\\\[-0.35em]~\dotfill\\\\f(-x)=(-x)^4-16(-x)^2+64\qquad \begin{cases}(-x)(-x)(-x)(-x)=x^4\\(-x)(-x)=x^2\end{cases}\\\\\\f(-x)=x^4-16x^2+64\impliedby \stackrel{\textit{same as the original}}{Even}$