First bring the 9 to the other side by subtracting it so you get the equation; x^2+10x-9=0 and you answer would be x=9 and x=1. you may have wrote the question own wrong? is the x^2 negative? if so i give my answer :)
Answer: {xI x ∈ R, 19 < x < 32}
Step-by-step explanation:
This notation is:
{xI condition1, condition2, ...}
The first condition is:
From what set we take the values of x?
From the set of real numbers.
x ∈ R
The other conditions are the limitations that we have for x, in this case:
19 < x < 32
Then we can write this as:
{xI x ∈ R, 19 < x < 32}
Answer: for question 1, i think you have to put yes because absolute value is always positive so it´s 6.5 and the opposite of -6.5 is 6.5
Step-by-step explanation:
Answer:
ok
Step-by-step explanation:
