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2 years ago

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Find the indicated limit, if it exists. lim(x->0) f(x), f(x)={5x-9 if x<0 {|2-x| if x>(orequalto)0 A. -9 B. -7 C. 2 D.

limit doesnt exist

1 answer:

jek_recluse [69]2 years ago

8 0

The limit does not exist. Because its left limit when x < 0 is -9, and the right limit is 2, which is not equal.

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Darrin is hanging 200 feet of Christmas garland on the fencing around his house. The fence has the shape of a rectangle and full

lianna [129]

Answer:

the width is 17.5 feet and the length is 82.5 feet.

Step-by-step explanation:

The house has a rectangular shape and we know that the length is 5 feet less than 5 times the width.

We will call the width x, thus, the length would be represented as 5x-5 (5 less than 5 times the width).

Since Darrin is going to hang garland around the perimeter of the house, we know that the perimeter is 2 times the length plus two times the width and this equals 200.

Let's write this in algebraic form

$width = x\\length= 5x-5\\Perimeter= 2width +2length=200\\200=2(x)+2(5x-5)\\200=2x+10x-10\\200=12x-10\\200+10=12x\\210=12x\\210/12=x\\x=17.5$

Therefore, the width is 17.5 feet.

Now, the length is 5x-5, thus substituting the 17.5 in this equation we have:

$5x-5=5(17.5)-5=87.5-5=82.5$ feet

Therefore, the width is 17.5 feet and the length is 82.5 feet.

7 0

2 years ago

Chen uses different strategies to add. He works with the addends 4,5,6,7

Lelu [443]

You can do 6 I guess. Then do 6+6=12

4 0

2 years ago

I need some assistance on this

Elena L [17]

Answer:

1650

Step-by-step explanation:

The shape is a pyramid on top of a prism.

Volume of a pyramid is V = ⅓ Ah, where A is the area of the base and h is the height of the pyramid.

Volume of a prism is V = Ah, where A is the area of the base and h is the height of the prism.

The base of both shapes is a right triangle. The area is:

A = ½ bh

A = ½ (22) (10)

A = 110

The height of the prism is 6. The height of the pyramid is 33 − 6 = 27. The total volume is:

V = (110) (6) + ⅓ (110) (27)

V = 1650

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3 years ago

What is the<br> the distance between a point at (-3,4) and a point at (2,-5)

zaharov [31]

<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the distance between a point at (-3,4) and a point at (2,-5) ?

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Let the two points be A and B .

And, let the distance be P .

Now, the distance P between the point A (-3,4) and the point B (2,-5) is

$\bf P \: = \sqrt{(-3 \: - \: 2)^2 \: + \: (4 \: + \: 5)^2}$

$\implies$ $\bf P \: = \sqrt{(-5)^2 \: + \: (9)^2}$

$\implies$ $\bf P \: = \sqrt{25 \: + \: 81}$

$\implies$ $\bf P \: = \sqrt{106}$

$\implies$ $\bf P \: = \: 10.3$

<h3>The distance between a point at (-3,4) and a point at (2,-5) is <u>1</u><u>0</u><u>.</u><u>3</u> . [Answer]</h3>

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2 years ago

Which table(s) show x and y in DIRECT PROPORTION?

Nuetrik [128]

Answer:

d and a

Step-by-step explanation:

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2 years ago