y = | x -5| + |x+5|
as range of x is
-5 < x < 5
we can see if we put x = 0 we get
y = 10
we put any value of x in given range first term is always negative without absolute. and 2nd term is always positive
so
y = | x -5| + |x+5|
= -( x-5) + x + 5
= - x + 5 + x + 5
= 10
so
y = 10 where -5 < x < 5
Answer: its probably 5
Step-by-step explanation:
simplify the fraction= 
(
). Then cancel the common factor of 4= 
, then evaluate the exponent = 5
Answer:
P(E or F)=P(E)+P(F)=0.41+0.47=0.88
4x^2-9
(2x+3)(2x-3)
To verify use distributed
2x(2x) +2x(-3)+3(2x)+3(-3)
4x^2-6x+6x-9
4x^2+0-9
4x^2-9
