A poster has an area of 432 square inches. The length x in inches is 6 inches longer than the width of the poster. Which can be
solved to determine the length, in inches, of the poster?
A) x^2 -6 =432
B) x^2 -6x =432
C) x^2 + 6 =432
D) x^2 +6x =432
1 answer:
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