If each book is $7.35 each then John would be able to buy 4 books which would be a total of $29.40
1km=1000metres
15km=15000 metres
15000/600=25
25-1=24 (minus the last one)
hope this helps :)
As measured by the MAD, the variability ratio is
(MAD of 6th grade heights)/(MAD of 7th grade heights) = 1.2/0.6 = 2.0
The 4th selection is appropriate:
2.0
Answer:
The surface of the prism is 84m²
Step-by-step explanation:
You have 4 figures here (two the same triangles)
you need to determine the surface of each and then sum it to one. This will be your final surface.
rectangles:
3*6= 18m²
5*6 = 30m²
4*6 = 24m²
triangles:
You need to determine the square of the triangles from the Heron's formula.
Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is
,
where s is the semi-perimeter of the triangle; that is,
.
So the permimeter of the triangle is
2p=4+5+3 = 12m
p = 6m
![S = \sqrt{p*(p-a)*(p-b)*(p-c)} = \sqrt{6*(6-3)*(6-4)*(6-5)} = \sqrt{6*3*2*1} =\sqrt{36} =6[m^{2} ]](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7Bp%2A%28p-a%29%2A%28p-b%29%2A%28p-c%29%7D%20%20%3D%20%5Csqrt%7B6%2A%286-3%29%2A%286-4%29%2A%286-5%29%7D%20%20%3D%20%5Csqrt%7B6%2A3%2A2%2A1%7D%20%3D%5Csqrt%7B36%7D%20%3D6%5Bm%5E%7B2%7D%20%5D)
So the surface of the prism is a total sum of all surfaces:
P = 18m²+30m²+ 24m²+2*6m² = 84m²
M(n+1)-n(m-1) (distribute m into (n+1))
mn+1m-n(m-1) (distribute -n into (m-1))
mn+1m-nm+1n (collect like terms) (the mn cancel out)
m+n