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3 years ago

2. Ten football teams are playing in a league.

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

90 games since each team would be playing 9 games (one against every other team)

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1. A point at (3, 2) is rotated 180° clockwise about the origin.

luda_lava [24]

1.) (-3,-2)
2.) 8.4m^3
3.) 37.7m^3

6 0

3 years ago

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

Mandarinka [93]

Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

$a_n = a_m + (n-m)d$

a3 = -12 and a8 = -37

First we find the common difference. So

$a_n = a_m + (n-m)d$

$a_8 = a_3 + (8-3)d$

$-37 = -12 + 5d$

$5d = -25$

$d = -\frac{25}{5}$

$d = -5$

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

6 0

3 years ago

Need help asap plzzz

Scilla [17]

$\sqrt{12}$
enters the irrational number category.

Integers numbers are the numbers without decimals between -infinity and infinity.

Natural numbers are the whole numbers from 1 to infinity.

Whole numbers are natural numbers + 0.

4 0

3 years ago

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The total cost of attending the movies, y, is directly proportional

Sergeu [11.5K]

Answer:

The slope should be 34.00.

Step-by-step explanation:

3 0

3 years ago

Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro

umka21 [38]

$|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%$

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3 years ago

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