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Bad White [126]
3 years ago
11

Write the equation of (-3, 3) and (3, -1) slope intercept form. Show all of your work

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
4 0
<span>y+3= -5x -20
y= -5x -23
compare with
y= mx +c
slope m=-5
intercept c=-23</span>
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a bag of grapes weighs 5/8 of a pound. Before any was eaten, the bag of grapes weighed 4 times this amount. What is the weight o
strojnjashka [21]
2.5 pounds or exact fraction 5/2 or 2 1/2 if you want a mixed fraction
6 0
3 years ago
Distance between the points
Harman [31]
To understand the distance formula, you first need to understand the Pythagorean Theorem. For a refresher, the theorem states that the square of the legs of a right triangle is equal to the the square of its hypotenuse (the side opposite the right angle), or in symbols:

a^2+b^2=c^2, where a and b are the lengths of the legs, and c is the length of the hypotenuse. In the context of the x-y plane, the legs of the triangle correspond to separate x and y values on the plane, and the hypotenuse corresponds to a straight line between two points on that plane.

To find the distance between the points you've listed, (2√5,4) and (1,2√3), we'll first need to find the "legs" of the triangle. To find the length of the x leg, we'll just need the distance between the x values of the points, which we find to be 2√5-1. We do the same for the y component, which ends up being 4-2√3. Now that we have our legs, we're ready to find the hypotenuse - or the distance.

Going back to Pythagorus's equation, we have:

(2 \sqrt{5}-1)^{2}+(4-2 \sqrt{3})^{2}=d^2

where d, the hypotenuse of the triangle, means "distance."

To solve for d, we take the square root of both sides:

d= \sqrt{(2 \sqrt{5}-1)^2+(4-2 \sqrt{3} )^2}

And from there, all that's left to do is solve the right side of the equation, which just ends up being rote calculation.

Edit: I'll go through the steps of that calculation here. We'll start by expanding each of the squared terms inside the radical:

(2 \sqrt{5}-1)^2=(2 \sqrt{5}-1)(2 \sqrt{5}-1)=(2 \sqrt{5}-1)2 \sqrt{5}-(2 \sqrt{5}-1)
=(2 \sqrt{5})^2-2 \sqrt{5}-2 \sqrt{5}+1=20-4\sqrt{5}+1

(4-2\sqrt{3})^2=(4-2\sqrt{3})(4-2\sqrt{3})=(4-2\sqrt{3})4-(4-2\sqrt{3})2\sqrt{3}
=16-8\sqrt{3}-8\sqrt{3}+(2\sqrt{3})^2=16-16\sqrt{3}+12

Putting those values back under the radical:

\sqrt{20-4\sqrt{5}+1+16-16\sqrt{3}+12}

Collecting constants:

\sqrt{49-4\sqrt{5}-16\sqrt{3}}

If you wanted an exact answer, this messy-looking thing would be it, and you can verify those results on WolframAlpha if you'd like. If you want an approximation, just enter that expression in to the online calculator of your choice, and it should give out the value of approx. <span>3.51325.</span>

In general, if you want to solve for the distance between two points (y_{1},x_{1}) and (y_{2},x_{2}), the formula is:

d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
4 0
3 years ago
The vertical and horizontal axes on a coordinate plane is called the...
Svetradugi [14.3K]

Answer:

the horizontal axis- X

the vertical axis- Y

4 0
3 years ago
Why is the central limit theorem important in statistics? a) Because for a large sample size n, it says the population is approx
Katarina [22]

Answer:

The correct option is (c).

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with a known mean and standard deviation and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by, the population mean.

And the standard deviation of the distribution of sample means is given by,

SD_{\bar x}=\frac{SD}{\sqrt{n}}

So, the most basic and main objective of the Central limit theorem is to approximate the sampling distribution of a statistic by the Normal distribution even when we do not known the distribution of the population.

Thus, the correct option is (c).

4 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues. 6, -18, 54, -162, +… Is this sequence arithmet
telo118 [61]

Answer:

Hello,

This sequence is geometric with a ratio of -3

the first term is 6

Step-by-step explanation:

u_1=6\\u_2=-18=6*(-3)=u_1*(-3)\\u_3=54=-18*(-3)=u_2*(-3)=u_1*(-3)^2\\u_4=-162=u_3*(-3)=u_1*(-3)^3\\\\...\\u_{n+1}=u_1*(-3)^n\\\\\displaystyle \sum\limits^\infty _{i=1}u_i = \lim_{n \to \infty} \sum\limits^n _{i=1}u_1*(-3)^{i-1}\\=6*\lim_{n \to \infty} \sum\limits^\infty _{i=1}(-3)^{i-1}\\=6*\frac{1-(-3)^n}{1-(-3)} \\=\dfrac{3}{2} *({1-(-3)^n)\\

serie does not converge.

7 0
3 years ago
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