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3 years ago

Andres bought 3 shirts that each cost the same amount and a pair of jeans that cost $40. The items he

Mathematics

2 answers:

Vsevolod [243]3 years ago

5 0

shirt-x

a.3s+40=106

b. 3s= 66

s=22

if my answer helps please mark as brainliest.

mart [117]3 years ago

3 0

Andres bought 3 shirts that each cost the same amount and a pair of jeans that cost $40. The items he
bought cost a total of $106 before tax was added.

PART A: Create an equation to find s, the cost of each shirt.

Reminder! Your equation should not have any spaces included in it. Ex. 4x+2=10

PART B: What is the cost of each shirt?

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Which relation represents a function?

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The answer is C. I think you have to start with a negative.

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If 2/x+ 3/y =13 and 5/x- 4/y = -2, then x+y equals

creativ13 [48]

Answer:

$x + y = \frac{5}{6}$

Step-by-step explanation:

Let:

$u = \frac{1}{x} \\ v = \frac{1}{y}$

This allows us to manipulate the equations like we normally would.

$2u + 3v = 13 \\ 5u - 4v = - 2 \\ \\ + 8u + 12v = 52 \\ + 15u - 12v = - 6 \\ 23u = 46 \\ u = 2 \\ \\ 2(2) + 3v = 13 \\ 4 + 3v = 13 \\ 3v = 9 \\ v = 3$

Then, we return the values where they belong.

$u = \frac{1}{x} \\ 2 = \frac{1}{x} \\ x = \frac{1}{2} \\ \\ v = \frac{1}{y} \\ 3 = \frac{1}{y} \\ y = \frac{1}{3}$

Finally, we add:

$\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$

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3 years ago

The length of a room is 20 feet and its width is 12 feet. What is the perimeter? A. 64 feet B. 32 feet. C. 52 feet. D. 44 feet.

gogolik [260]

By adding all sides of the rooms walls you get 64 feet for your perimeter 20+20+12+12=64 feet

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4 years ago

I need help with this problem from the calculus portion on my ACT prep guide

LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r$

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

$\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}$

Then the limit is:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert$

We can simplify the expressions inside the absolute value:

$\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}$

Since none of the terms inside the absolute value can be negative we can write this with out it:

$\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}$

Now let's re-writte n/(n+1):

$\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}$

Then the limit we have to find is:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}$

Note that the limit of 1/n when n tends to infinite is 0 so we get:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4$

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

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1 year ago

A square park has an area of 1⁄16 square miles and a length of 1⁄4 mile. What is the width of the park?

Vikentia [17]

Width: 1/4 Explanation: First you set up the problem as 1/16 divided by 1/4, then you change the division sign to multiplication and then you flip the second fraction which is 1/4, you should have 4/1, next you have a problem like 1/16 x 4/1 1x4= 4 and 16x1=16, did you get 1/4 as your product? If you didn’t, repeat the steps and try as many times until you get it, it is the only way to learn. Thank you for asking this question and have a great Evening! :)

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3 years ago