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2 years ago

7

a bag of grapes weighs 5/8 of a pound. Before any was eaten, the bag of grapes weighed 4 times this amount. What is the weight o

f the original bag of grapes

1 answer:

strojnjashka [21]2 years ago

6 0

2.5 pounds or exact fraction 5/2 or 2 1/2 if you want a mixed fraction

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A plus 5 equals negative 5a plus 5

jenyasd209 [6]

A+5=5a+5 Subtract a from each side
5=5a+5 Subtract 5 from each side
0=5a Divide each side by the number before the variable to get it alone.
--- ---
5 5
a=0

4 0

3 years ago

Read 2 more answers

Which sequence of transformations will produce similar but not congruent figures?

RoseWind [281]

A dilation would produce<span> a </span>similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and f<span>igure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.</span>

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3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

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3 years ago

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How do i write b + 3 = b^2 in verbal expression

igor_vitrenko [27]

Answer:

b plus 3 is equal to b squared

7 0

3 years ago

Ava borrowed some money from her friend in order to help buy a new video game system. Ava agreed to pay back her friend $2 per w

nydimaria [60]

We know that Ava is paying $2 dollars per week so if L is the money that she owes and t is the number of weeks, and I is the initial debt so we can write an equation like:

$L=I-2t$

Now we can replace the info we have to find the value of I so:

$10=I-2(5)$

and we solve for I

$\begin{gathered} I=10+10 \\ I=20 \end{gathered}$

So the final equation will be:

$L=20-2t$

8 0

1 year ago