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3 years ago

7

The unchanging value of a ratio between two proportional quantities

1 answer:

Llana [10]3 years ago

5 0

The unchanging value of a ratio between two proportional quantities is known as a constant

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If y = x2 + x -1, find y if x = 3. y =

marishachu [46]

Answer:

y=3

Step-by-step explanation:

y = 3x2 + 3x-1

y = 6 + -3

y = 3

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3 years ago

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You begin with $100.00 at the beginning of the month. This amount is cut in half each day. How much will you have on day 7? Begi

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Day 1 - 100
Day 2 - 50
Day 3 - 25
Day 4 - 15
Day 5 - 10
Day 6 - 5
Day 7 - 2.5

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3 years ago

What is 845 rounded to the nearest ten

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3 years ago

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Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

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3 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista

Kamila [148]

40mph for Car B I think. 45mph for Car A. 45(mph) times 4(h) is 180(distance) and 40 times 4.5 is also 180. Sorry if I'm wrong.

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4 years ago