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Kruka [31]
3 years ago
6

What is 563 rounded to nearest 10

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0
The answer is 560 because if say you had to round 567 to the nearest ten, that would be 570 because the nearest 10 to 67 is 70, but here you have 563 so the nearest 10 to 63 is 60 :)

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Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:
fredd [130]
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
6 0
2 years ago
Write an expression that represents the area of a circle with radius 3x^3. (For any circle with radius r, a=π r^2 = π .r .r ^.)
aalyn [17]

9514 1404 393

Answer:

  B. 9πx^6

Step-by-step explanation:

Putting the given radius into the area formula gives ...

  A = πr^2

  A = π(3x^3)^2 = π(3^2)(x^(3·2))

  A = 9πx^6

6 0
3 years ago
Select the correct answer.
ch4aika [34]

Answer:

home inventory

Step-by-step explanation:

the insurance company wants to know what they are going to be insuring

4 0
3 years ago
Read 2 more answers
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
3 years ago
How many are 4 x 4 ?​
Ne4ueva [31]

Answer:

16

Step-by-step explanation:

6 0
3 years ago
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