Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
9514 1404 393
Answer:
B. 9πx^6
Step-by-step explanation:
Putting the given radius into the area formula gives ...
A = πr^2
A = π(3x^3)^2 = π(3^2)(x^(3·2))
A = 9πx^6
Answer:
home inventory
Step-by-step explanation:
the insurance company wants to know what they are going to be insuring
Answer:
The graph of the function 
has a minimum located at (4,-3)
Step-by-step explanation:
we know that
The equation of a vertical parabola in vertex form is equal to
where
a is a coefficient
(h,k) is the vertex of the parabola
If a > 0 the parabola open upward and the vertex is a minimum
If a < 0 the parabola open downward and the vertex is a maximum
In this problem
The coefficient a must be positive, because we need to find a minimum
therefore
Check the option C and the option D
Option C
we have
Convert to vertex form
Factor the leading coefficient
The vertex is the point (4,-3) ( is a minimum)
therefore
The graph of the function has a minimum located at (4,-3)
Answer:
16
Step-by-step explanation:
