On google, it says 8.463.
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
The answer to your question is the letter C
Step-by-step explanation:
Data
a = 4.5 u
b = 5.8 u
c = 3 u
Process
1.- Calculate the volume of the rectangular prisms
Formula
Volume = a x a x c
Substitution
Volume = 4.5 x 4.5 x 3
Result
Volume = 60.75 u³
But there are two rectangular prism
Total volume = 2 x 60.75
= 121.5 u³
2.- Calculate the volume of the triangles
Formula
Volume = base x width x height
Substitution
Volume = 5.8 x 3 x 4.5
Result
Volume = 78.3 u³
3.- Total volume
Volume = 121.5 + 78.3
= 199.8 u³
Answer:
THE ANSWER IS -21
Step-by-step explanation: BECAUSE IF YOU TAKE -4P -15P=-19P
-19P-2R=-21