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m_a_m_a [10]
3 years ago
5

Write the equation for a circle with it's center at (9,7) and with a solution point at (-6,2)

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

The equation for a circle is

(x-h)^2+(y-k)^2=r^2

We have an h, k, x, and y; we need to find r-squared.  Filling in:

(-6-9)^2+(2-7)^2=r^2  which simplifies to

-15^2+-5^2=r^2  which simplifies to

225+25=r^2  which means that

r^2=250

Our equation, then, is

(x-9)^2+(y-7)^2=250

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Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104. So I have to find r. But is this right: 7104 = 444r^4 r^4 = 16
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Third term = t3 = ar^2 = 444           eq. (1)

Seventh term = t7 = ar^6 = 7104         eq. (2)

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