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stellarik [79]
3 years ago
12

Dividing by one digit number page 53

Mathematics
2 answers:
Effectus [21]3 years ago
7 0

U FORGOT TO UPLOAD A PICTURE OR SOMETHing

uysha [10]3 years ago
5 0

53/2 is 26 r 1 if that's what you're asking

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Samantha walks a total of 2/3 mile to get to and from school each day . Find the total number of miles that Samantha walked to a
algol13

Answer:

3 1/3 miles

Step-by-step explanation:

If Samantha walks 2/3 miles everyday and they are asking for 5 days

2/3miles · 5days = 3 1/3 or 10/3 miles

4 0
3 years ago
PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.
grin007 [14]

Answer:

It should be 9 m :)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
) What is the GCF of 36 and 60?<br> 4<br> 6<br> 12<br> 18
My name is Ann [436]

Answer:

12

Step-by-step explanation:

List out the factors of each

36: 1,2,3,4,6,9,12,18,36

60: 1,2,3,4,5,6,10,12,15,20,30,60

the highest number they both have in common is 12

8 0
3 years ago
For a data set of weights​ (pounds) and highway fuel consumption amounts​ (mpg) of eleven types of​ automobile, the linear corre
Zina [86]

Answer:

gay i am

Step-by-step explanation:

5 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
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