Answer: W = 2/L
Isolate the variable by dividing each side by factors that don't contain the variable.
Well you haven't really given us a question that requires a "quantifiable" answer. 2 ounces is roughly equivalent to 60 grams. 2 ounces of ketchup wouldn't be an awful lot of ketchup. I'm sure that you'd remain healthy despite eating 2 ounces of ketchup along with your potato wedges.
According to the American Heart Association, women should only have about 25 grams of sugar per day. In 100g of ketchup there would be about 22g grams of sugar. If you were to eat roughly 60g of ketchup, you'd only be digesting about 13.2 grams of sugar. Now, potato wedges could also contain sugar, but you haven't stated how many grams or kilograms of potato wedges you'd be eating, so I wouldn't be able to tell you whether your meal contains too much sugar.
Solution :
The data is normally distributed.
The standard deviation is 18 days
Here the data is normally distributed and 54 days is 3 days of standard deviation.
Therefore, the percentage of the births that would be
within the 54 days of the mean
length is given by :
= P( -3 < Z < 3)
= 0.9544
= 95 %
Therefore, about 95% of the births would be
within 54 days of the men
length.
Answer:
342.8
Step-by-step explanation: