(4 + y = 19) what is y

When building a house, the number of days required to build varies inversely with with the number of workers. One house was buil

Helga [31]

Let d represent number of days and n represent number of workers.

We have been given that when building a house, the number of days required to build varies inversely with with the number of workers.

We know that the equation $y=\frac{k}{x}$ represents the relation where y is inversely proportional to x and k is the constant of proportionality.

So our required equation would be $d=\frac{k}{n}$

Upon substituting our given values, we will get:

$19=\frac{k}{35}$

$k=19\cdot 35$

$k=665$

Since constant of proportionality is 665, so our equation would be $d=\frac{665}{n}$ .

To find the number of days it will take to build a similar house with 5 workers, we will substitute $n=5$ in our equation as:

$d=\frac{665}{5}$

$d=133$

Therefore, it will take 133 days for 5 workers to build a similar house.

5 0

3 years ago

A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (6, 5). What is

OLga [1]

Answer:

The vector joining the ship to the rock is t= 7 i + 5 j

The direction is 0.9505 radians east of north.

Step-by-step explanation:

The position vector of the ship:

r= 1 i + 0 j

The position vector of the ship:

s= 6 i + 5 j

The vector joining the ship to the rock is:

t = r + s

t = (1 i + 0 j) + (6 i + 5 j)

t = 7 i + 5 j

The bearing of the rock to the ship is:

Θ= $\frac{ \pi}{2} - arctan (\frac{5}{7})$ = 0.9505 radians

4 0

3 years ago

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

4 years ago

The value of t can be determined by using the expression 2.75s. Which table represents the relationship between the values of t

ad-work [718]

This isn't a table, but you can easily make it into one.

s t
-2 -5.5
-1 -2.75
0 0
1 2.75
2 5.5

6 0

3 years ago

Read 2 more answers

How many times does 15 go into 85 evenly?

ANEK [815]

Answer:5 1/3 times

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers