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3 years ago

A line that intersects one of two parallel lines intersects the other also.

Mathematics

1 answer:

IceJOKER [234]3 years ago

8 0

Answer:

Never

Step-by-step explanation:

It is not possible for one out of two parallel lines to be cut by a transversal, because eventually it would have to intersect

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Solve the equation.

Zina [86]

Answer:

x=5

Step-by-step explanation:

esa es la respuesta correcta

7 0

3 years ago

How do you solve the polynomial (4x to the third power) (-5x)

Novay_Z [31]

Multiply the 4 and 5, and add the exponents

8 0

3 years ago

What is the area of the trapezoid?

tensa zangetsu [6.8K]

Answer:

24 square units

Step-by-step explanation:

For Trapezoid

a = 8

b = 4

h = 4

Area of Trapezoid

A = a + b/2 * h

= 8 + 4/2 * 4

= 12/2 *4

= 6 * 4

= 24

Thus, the area of the trapezoid is 24 square units

6 0

3 years ago

A rectangle has a length of x + 7 and a width of 2x -3 if its perimeter perimeter is 32 what is the value of 3x

Fittoniya [83]

$Answer: \\ We \: have \: an \: equation:2(x + 7 + 2x - 3) = 32 \\ \Leftrightarrow 2(3x + 4) = 32 \\ \Leftrightarrow 3x + 4 = 16 \\ \Leftrightarrow 3x = 12$

5 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).The equation of a

alina1380 [7]

ANSWER

$\begin{gathered} center=(-3,-5) \\ r=4 \end{gathered}$

EXPLANATION

Given;

$x^2+y^2+6x+10y+18=0$

The standard equation of circle of a circle centered at (h,k) with radius r is;

$(x-h)^2+(y-k)^2=r^2$

Re-write the given equation in the standard form, we have;

$\begin{gathered} x^{2}+y^{2}+6x+10y+18=0 \\ x^{2}-6x+(\frac{6}{2})^{2}+y^{2}+10y+(\frac{10}{2})^{2}=-18+9+25 \\ (x-3)^2+(y-5)^2=4^2 \end{gathered}$

Hence, h=-3, k=-5, radius is 4

7 0

1 year ago