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2 years ago

What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y + 1 = 0?

Mathematics

1 answer:

Bezzdna [24]2 years ago

7 0

Answer:

The answer is

Step-by-step explanation:

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

4x + y + 1 = 0

y = - 4x - 1

Comparing with the above formula

Slope / m = - 4

Since the lines are parallel their slope are also the same

That's

Slope of the parallel line is also - 4

Equation of the line using point ( 1 , 2) is

y - 2 = -4(x - 1)

y - 2 = - 4x + 4

4x + y - 2 - 4

We have the final answer as

Hope this helps you

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2 years ago

Subtract the second expression from the first . (5x^2-3x+5) - (3x^2-4x-7)

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3 years ago

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musickatia [10]

Answer:

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2 years ago

What was Zane's unit rate, in words per minute, on each test?

AfilCa [17]

Answer:

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Step-by-step explanation:

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2 years ago

Subject: Mathematics

lina2011 [118]

$\\ \sf\longmapsto \dfrac{1}{x-1}>4$

Multiply x-1 on both sides

$\\ \sf\longmapsto \dfrac{1}{x-1}\times (x-1)> 4(x-1)$

$\\ \sf\longmapsto 1>4(x-1)$

$\\ \sf\longmapsto 1> 4x-4$

Add 4 on both sides

$\\ \sf\longmapsto 1+4> 4x$

$\\ \sf\longmapsto 5> 4x$

Divide both sides by 4

$\\ \sf\longmapsto \dfrac{5}{4}>x$

$\\ \sf\longmapsto x< \dfrac{5}{4}$

Now

ATQ to the equation $\bf \dfrac{1}{x-1}$ x should be greater than 1 .Because if it becomes 1 then the denominator will be 0 which is impossible.

Hence x>1

Thus

$\\ \sf{:}\!\implies 1$

Now

$\\ \therefore\boxed{\bf x\epsilon \left(1,\dfrac{5}{4}\right)}$

6 0

2 years ago

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