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2 years ago

Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second

1 answer:

8 0

$s(t)= \int\limits^{35}_0 {v(t)} \, dt \\ =\int\limits^{35}_0 {(20+5cos(t))} \, dt \\ =[20t+5sin(t)]^{35}_0 \\ =(20(35)+5sin(35))-(20(0)+5sin(0)) \\ =700+2.868=702.868 \, feet$

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What is the solution for the equation?<br> a+8/3=2/3

Readme [11.4K]

A+8/3 = 2/3
Or, (3a+8)/3 = 2/3 [taking LCM]
Or, 3a+8 = 2 [3 in both denominators are cancelled]
Or, 3a = 2-8
Or, a = -6/3
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3 years ago

Help!!

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

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Step-by-step explanation:

Required

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Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

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Collect like terms

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Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

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Divide both sides by -2

$x = 4$

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Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

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2 years ago

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Step-by-step explanation: I went to desmos calculator and typed in your equation and it automatically gave me this graph. (See Picture for more details.)

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2 years ago

Read 2 more answers