Answer:
79°
Step-by-step explanation:
Remember, the sum of all the angles in a triangle is 180
So 180-RST-RTS=180-53-48=79
Answer:
(1,2)
Step-by-step explanation:
x value -2+4 /2 = 1
y value -2+6/2 = 2
Answer:
PQ = 34.4
Step-by-step explanation:
First, we know that the angles in a triangle add up to 180 degrees. Therefore, angle M = 48 and angle R = 74
Next, because there is a corresponding angle in each triangle, they are similar. This means that the ratios between corresponding sides are the same. For example, the side opposite angle O (MN) over the side opposite angle R (PQ) is equal to the side opposite angle N (OM) over the side opposite angle Q (RP)
This can be written as MN/PQ = OM/RP. Note that both the numerators are on the same triangle, and MN and PQ correspond, as well as OM and RP.
We are given MN, NO, and QR. Because NO is opposite a 48 degree angle (angle M) as well as QR (angle P), we can say that NO/QR = another ratio of a pair of corresponding sides. Because we want to find PQ, and both PQ and MN are opposite 74 degree angles, we can say that
NO/QR = MN/PQ
Thus,
11/27 = 14/PQ
multiply both sides by PQ to remove a denominator
PQ * 11/27 = 14
multiply both sides by 27 to remove the other denominator
PQ * 11 = 14 * 27
divide both sides by 11 to isolate the PQ
PQ = 14 * 27 /11
PQ = 34.4
There are two different answers that you could be looking for.
You might be asking how many different meals can be served at the banquet,
or you might be asking literally how many 'ways' there are to put meals together.
I'm going to answer both questions. Here's how to understand the difference:
Say you have ten stones, and you tell me "I'll let you pick out two stones
and take them home. How many ways can this be done ?"
For my first choice, I can pick any one of 10 stones. For each of those . . .
I can pick any one of the 9 remaining stones for my second choice.
So the total number of 'ways' to pick out two stones is (10 x 9) = 90 ways.
But let's look at 2 of those ways:
-- If I pick stone-A first and then pick stone-G, I go home with 'A' and 'G'.
-- If I pick stone-G first and then pick stone-A, I still go home with 'A' and 'G'.
There are two possible ways to pick the same pair.
In fact, there are two possible ways to pick <em><u>every</u></em> pair.
So there are 90 <em><u>ways</u></em> to pick a pair, but only 45 different pairs.
That's the reason for the difference between the number of <em><u>ways</u></em> the
committee can make their selections, and the number of different <em><u>meals</u></em>
they can put together for the banquet.
So now here's the answer to the question:
-- Two appetizers can be selected in (6 x 5) = 30 ways.
(But each pair can be selected in 2 of those ways,
so there are only 15 possible different pairs.)
-- Three main courses can be selected in (10 x 9 x 8) = 720 ways.
(But each trio can be selected in 3*2=6 of those ways,
so there are only 120 possible different trios.)
-- Two desserts can be selected in (8 x 7) = 56 ways.
(But each pair of them can be selected in 2 of those ways,
so there are only 28 possible different pairs.)
-- The whole line-up can be selected in (30 x 720 x 56) = <em>1,209,600 ways</em>.
But the number of different meals will be (30 x 720 x 56) / (2 x 6 x 2) =
(15 x 120 x 28) = <em><u>50,400 meals</u></em>.
Answer: Yea I guess because you did everything right.
Step-by-step explanation:
