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serg [7]
3 years ago
6

What property was used to solve the equation?

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

Multiplication sorry I late

Step-by-step explanation:

stellarik [79]3 years ago
6 0
What’s the equation
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The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which inequa
Anna35 [415]

Answer:

x+y < 28

Step-by-step explanation:

1. Look at your variables: x is the first number and y is the second.

2. Know the limits: It says it has to be NO MORE than 28, so the inequality has to be less than (<) 28. And it says that the SUM of 2 numbers (in this case x and y), is no more than 28, so you know there's some addition between the two.

3. Write out your inequality: x+y < 28

7 0
3 years ago
How do i solve this? (1/3x-11)^(1/2)=5
photoshop1234 [79]
(\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108
4 0
3 years ago
Read 2 more answers
The Travers are adding a new room to their house. The room will be a cube with volume
Damm [24]

Answer:

$1620

Step-by-step explanation:

The volume (V) of a cube is calculated as

V = s³ ( s is the length of the side )

Here V = 5832 , then

s³ = 5832 ( take cube root of both sides )

s = \sqrt[3]{5832} = 18 ft

The area of the square floor is then

area = 18² = 324 ft²

cost = 324 × $5 = $1620

4 0
3 years ago
Please Help............................................
kipiarov [429]
I had the same thing to do :) im doing mine now, if needed just pm me and ill help more, just right about the proposes  you  see

3 0
3 years ago
Find the sum of the coefficients in the expansion of (x+1)^12
MariettaO [177]

Answer:

<h2>2¹²</h2>

Step-by-step explanation:

The sum of the coefficients in the expansion of (x+1)^12:

= 12C0 + 12C1 + 12C2 + . . . + 12C11 + 12C12

the formula says that this sum equal to 2¹².

Other examples

The sum of the coefficients in the expansion of (x+1)^3:

3C0+3C1+3C2+3C3

=8 = 2³

The sum of the coefficients in the expansion of (x+1)^4:

4C0+4C1+4C2+4C3+4C4

=16 = 2⁴

:)

4 0
4 years ago
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