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3 years ago

Which expressions are equivalent to 9x(2+y) ?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

<span>18x+9xy is correct all Roots are to x=0 and y=-2
(9x⋅2)+(9x⋅y) is correct </span>Roots are to x=0 and y=-2

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(-3c+6) + (-c+8) simplify with a step by step please

mel-nik [20]

Step-by-step explanation:

$= ( - 3c + 6) + ( - c + 8)$

$= - 3c + 6 - c + 8$

$= - 3c - c + 6 + 8$

= -4c + 14

hence -4c + 14 is the answer ...

hope it helped !!

6 0

2 years ago

Common difference of 1 10 100 1000 What is the answer.

Maksim231197 [3]

Answer:

each time the numbers are being multiplied by 10

Step-by-step explanation:

1 × 10 = 10

10 × 10 = 100

100 × 10 = 1,000

hope this helps :)

5 0

3 years ago

Who whats to talk <br> im here<br> .0.

Vsevolod [243]

Answer:

:( :( :(

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which of the following is the function of f(x)?

Natasha2012 [34]

Answer:

f(x) = 8(x-3)

Step-by-step explanation:

F^ -1 ( x) = x/8 +3

Let y = x/8+3

To find the inverse

Exchange x and y

x = y/8+3

Solve for y

x-3 = y/8+3-3

x-3 = y/8

Multiply each side by 8

8(x-3) = y/8 * 8

8(x-3) = y

The inverse of the inverse is the function so

f(x) = 8(x-3)

5 0

3 years ago

Read 2 more answers

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago