Answer:
X= 75, Y=30 there you go!
Step-by-step explanation:
Sorry I was moving around taking the picture and my handwriting is sloppy. But I hope you understand how I got the answer
<span>The function which has a constant halving time is in the following form
</span>

Where: A₀ is the <span>initial amount
h is the half life time or the halving time.
</span><span> t is the time
</span> A(t) <span>the amount<span> that remains at time t
</span></span>
The previous function represents an Exponential decay<span> function.
</span>
so, The correct answer is option B. <span>
Exponential decay</span>
Answer:
The formula for this quadratic function is x*2 +6x+13
Step-by-step explanation:
If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this
y= a (x-h)*2 + K
Quadratic function looks like this
y= ax*2 + bx + c
So let's find the a
y= a (x-h)*2 + K where
y is 13, x is 0, h is -3 and K is 4
13= a (0-(-3))*2 +4
13=9a +4
9=9a
9/9=a
1=a
The quadratic function will be
y= 1(x+3)*2 + 4
Let's get the classic form
(x+3)*2 = (x+3)(x+3)
(x*2+3x+3x+9)
x*2 +6x+13
f(0) = 13