<em>Inscribing</em> a<u> square</u> in a given<u> circle</u> is a method of drawing the required <u>square</u> within the <em>circumference</em> of the <u>circle</u>. Thus the <em>appropriate</em> answer is Option A.
<u>Inscribing</u> a <u>square</u> in a given <u>circle</u> is a method of <em>drawing</em> the required <em>square</em> within the <em>circumference</em> of the circle. This requires the following stipulated <u>steps</u> to produce a required<u> image</u>.
A <u>square</u> is a <em>plane shape</em> with an <u>equal</u> length of <u>sides</u>. So that the size of an <u>inscribed</u> <u>square</u> is determined by the <em>diameter</em> or<em> radius</em> of the <u>circle</u>.
Considering the appropriate process to be followed, then Cassandra should create a <em>perpendicular bisector</em> of BC. Then use the <u>points</u> of <em>intersection</em> of the p<em>erpendicular bisector</em> with the <u>circle</u>, along with <u>points</u> B and C, to <u>draw</u> the <u>square</u>.
Thus, the option that <u>summarises</u> the <em>basic process</em> is option A.
For more clarifications on inscribing a square in a given circle, visit: brainly.com/question/63415
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Answer:
0.4615
Step-by-step explanation:
1/780 x 360 = 0.4615
<h3>
Answer:</h3>
f(x) = 11.93·1.42^x
<h3>
Step-by-step explanation:</h3>
I entered the data into a graphing calculator and made use of its exponential regression function to find the coefficients of ...
... y = a·b^x
It told me ...
... a ≈ 11.9304, b ≈ 1.41885
In accordance with the problem statement, these values are rounded to hundredths to get the answer.
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<em>Comment on the graph</em>
The given points and two curves are show. The solid red curve is the exponential regression curve produced by the calculator. The dotted blue curve is the one you get when you round the numbers to the nearest hundredth.
Your answer would be the very first one since t would represent time(minutes) which is the x-axis, that's how you find the domain. And since your domain starts as a closed dot at 0 and ends as a closed dot at 14 t- 0<= t <= 14
Hope this was helpful :)