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Akimi4 [234]
2 years ago
12

What is 1/10 the value of 4 in 42,000

Mathematics
2 answers:
tester [92]2 years ago
8 0
The answer would be 34,612
labwork [276]2 years ago
5 0
The answer is 4000 because the value of 4 is 40000 so times that by 1/10 gives you 4000
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76.75 is 25% of 307

Step-by-step explanation:

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2. A jeweler bought an antique watch for $500. He then sold it in his store $850. What was the percent of change in the price of
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The middle point of BC is (0,2), the midpoint of CD is (1,0)
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3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
2 years ago
N/2 + 3 = 7 (n/2 is a fraction)
pishuonlain [190]

Answer:

n=8

Step-by-step explanation:

n/2+3=7

-3 -3

n/2 = 4

*2 *2

n=8

3 0
3 years ago
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