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3 years ago

Estimate. 2.16 + 8.9

Mathematics

1 answer:

ASHA 777 [7]3 years ago

6 0

Answer:

11.06 or 11

Step-by-step explanation:

.16 plus .9 is 1.06. 1.06 plus 2 plus 8 is 11.06. round to 11

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ruslelena [56]

Your answer is 9 percent

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3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

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Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

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3 years ago

Zack delivers mail for the post office. Every day he walks a 7-mile route. How many miles does Zack walk in one month if he work

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If Zack walks a 7-mile route every day, and he goes on for 22 days, the answer is 154, because you are multiplying 7 by 22 (7 x 22 = 154).

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3 years ago

Which statements accurately describe the graph? Check all that apply. The dependent variable, frequency, is placed on the horizo

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Answer:

B C D

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3 years ago

Read 2 more answers

John uses 8/6 ounces of milk for his recipe . Mya uses 4/3 ounces of milk for her recipe. who uses more milk? explain your answe

Aleks04 [339]

To compare the fractions we need to find a common denomanator.
This means we need to find a common number (to the denomanator) in each number set of times tables.
In this case we can use 6 as a common denomator.

One of out fractions is already out of 6 so we just need to convert the other one.
We can just double 4/3 to give us 8/6.

We can now compare the data, we have 8/6 and 8/6.
These fractions show that both John and Mya use the same amount of milk for their recipies, this being 8/6 or 1 1/3 as a mixed number.

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3 years ago