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Anna [14]
3 years ago
14

Suppose f is an exponential function and:

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0

Answer:  a) b= p(1 + r)^1 b) c= p(1 + r)^n c) d= p(1 + r)^m d) b^n=c

Step-by-step explanation:

Since f is an exponential function.

So, it is expressed as

f = p(1 + r)^

Here f is the present value

p is the initial value

r is the rate of growth per time period

t is the time period.

(a) b represents the 1-unit growth factor for f.

b= p(1 + r)^1

(b) c represents the n n-unit growth factor for f.

c= p(1 + r)^n

(c) d represents the m m-unit growth factor for f.

d= p(1 + r)^m

Write a formula that expresses c in terms of b.

Since

b=p(1+r)^1\\\\So,\\\\b=p(1+r)^{n\times \frac{1}{n}}\\\\b=(p(1+r)^n)^{\frac{1}{n}}\\\\b=c^{\frac{1}{n}}\\\\b^n=c

Hence, a) b= p(1 + r)^1 b) c= p(1 + r)^n c) d= p(1 + r)^m d) b^n=c

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Which two integers are 7 units away from the number 5 on a number line? A-2 and 2 O B-2 and c. -- and D. -2 and​
Sloan [31]

Answer:

-2 and 12

Step-by-step explanation:

To find the two numbers which are 7 units away from 5, add 7 to 5 and subtract 7 from 5

5+7 = 12

5-7 = -2

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2 years ago
12x+7&lt;−11 OR 5x−8&gt;40<br> solve for x
kipiarov [429]

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

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6 0
3 years ago
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Which parabola has the graph shown?<br><br> I think the answer is C. however, I'm not 100% sure.
NemiM [27]

x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex

We have the vertex (-4, -1), therefore we have:

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7 0
3 years ago
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
Please help &lt;3 Thanks!!
iVinArrow [24]

what dou you need?????????

7 0
3 years ago
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