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olga55 [171]
3 years ago
15

Help me please I really need help

Mathematics
2 answers:
Crank3 years ago
8 0
I think the answer is A
lianna [129]3 years ago
7 0

Answer:

im pretty sure its A

Step-by-step explanation:

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A

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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!!
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\text{Use}\\\\a^2-b^2=(a-b)(a+b)\\\\i=\sqrt{-1}\to i^2=-1\\---------------------\\\\x^2+25=x^2+5^2=x^2-(-1)(5^2)=x^2-(i^2)(5^2)=x^2-(5i)^2\\\\\boxed{x^2+25=(x-5i)(x+5i)}

8 0
2 years ago
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they
sp2606 [1]

mechanic #1's rate = x

mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)

20x = money earned by mech#1

and mechanic #2 worked for 5 hours

5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means

x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150

1900 - 15y = 1150

-15y = 1150 - 1900

-15y = -750

y = -750/-15

y = 50 $/hr

Now use this to solve for x

x + y = 95

x + 50 = 95

x = 95 - 50

x = 45 $/hr

mech#1 charged 45$/hr

mech #2 charged 50$/hr

4 0
3 years ago
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