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3 years ago

Rewrite with positive exponents a^-3 b^-5

Mathematics

1 answer:

amm18123 years ago

6 0

Answer:

1/a^3 and 1/b^5

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A radioactive substance decays at a rate of 25% every 10 years. Which equation represents the amount of the substance (S) remain

Lelechka [254]

Answer:

$y = 100 * (0.75)^{30$

Step-by-step explanation:

Given

$a =100$ --- Initial Amount

$r= 25\%$ every 10 years

Required

The remaining amount after 300 years

To do this, we make use of:

$y = a(1 - r)^T$

Where

r = decay rate

T = the period of decay

In 300 years, there are 30 periods of 10 years.

i.e.

$T = \frac{300}{10}$

$T = 30$

$y = a(1 - r)^T$

$y = 100 * (1 - 25\%)^{30$

$y = 100 * (1 - 0.25)^{30$

$y = 100 * (0.75)^{30$

3 0

3 years ago

If the input is -8, what is the output? the equation is : f(x) = -6x – 3

Phantasy [73]

Answer:

f(-8) = 45

Step-by-step explanation:

Step 1: Define

f(x) = -6x - 3

x = -8

Step 2: Substitute and Evaluate

f(-8) = -6(-8) - 3

f(-8) = 48 - 3

f(-8) = 45

6 0

3 years ago

Read 2 more answers

Based on the model N(1154,81) describing steer weights, what are the cutoff values for

skad [1K]

Can’t see the model.......................

7 0

3 years ago

Solve -5t = 60 65 -6 6 55

defon

When you are asked to solve an equation, you need to isolate the variable which is t in this case. To isolate t, you would divide both sides by -5 and be left with t=-6 which is the final answer.

I hope this helps.

8 0

3 years ago

30 POINTS! Combine the like terms of the 2 questions below:

astraxan [27]

Answer:

$\tt 1)\: \boxed{\tt 4y+10}$

$\tt 2)\:\boxed{\tt 0.5x^4+10.5}$

Step-by-step explanation:

1) y + 4 + 3(y + 2)

Expand:-

$\tt y+4+3y+6$

Combine like terms:-

$\tt y+3y+4+6$

$\boxed{\tt 4y+10}$

2) 0.5(x⁴ - 3) + 12

Expand:-

$\tt 0.5x^4-1.5+12$

Add/Subtract Numbers:-

$\boxed{\tt 0.5x^4+10.5}$

___________________

5 0

2 years ago