Answer:
No real roots.
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Quadratic Formula:
<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-3x² + 2x = 1
<u>Step 2: Rewrite in Standard Form</u>
- Subtract 1 on both sides: -3x² + 2x - 1 = 0
<u>Step 3: Define</u>
a = -3
b = 2
c = -1
<u>Step 4: Find roots</u>
- Substitute in variables:
- Exponents:
- Multiply:
- Subtract:
Here we see that we cannot take the square root of a negative number. We will get no real roots and only imaginary ones.
Answer:
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Answer:
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Convert each mixed number to an improper fraction
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Convert 6&1/2 to an improper fraction
6&1/2 = (6*2+1)/2
6&1/2 = (12+1)/2
6&1/2 = 13/2
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Do the same for 9&1/4
9&1/4 = (9*4+1)/4
9&1/4 = (36+1)/4
9&1/4 = 37/4
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Now multiply the improper fractions 13/2 and 37/4. Multiply straight across
(13/2)*(37/4) = (13*37)/(2*4)
(13/2)*(37/4) = 481/8
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The last step is to use long division to find the mixed number equivalent of 481/8
Or we an say
60*8 = 480
So 60*8+1 = 480+1
which means
481/8 = (480+1)/8 = 480/8+1/8 = 60&1/8
Making the final answer to be choice C
Another way to get the answer is to convert 481/8 into a decimal to get 60.125 and then convert that back to a mixed number. You should get 60&1/8