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Veseljchak [2.6K]
2 years ago
13

I don’t understand this

Mathematics
1 answer:
Maslowich2 years ago
3 0
I'm guessing it's = cause I think that the space between the parenthesis is 0. but I'm just guessing
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Please help on this math problem
Arte-miy333 [17]

Answer:

1680 in^3

Step-by-step explanation:

SO you got the triangle

24*10=240

240/2=120

now we just need to find the area

There is a formula but I think this is easier

So theres a rectangle with a length of 14

So if you think of the triangle as the base, you just need 14 triangles stacked up to make up the volume

So 120*14=1680

So the volume is 1680

6 0
2 years ago
I don’t know the answer to that one can you help me please
dybincka [34]

Answer:

16/45

Step-by-step explanation:

Step 1:  When dividing fractions, use “KFC”.  It means Keep the first fraction, Flip the second one, and  

              Change it to multiplication

-4/20 ÷ -9/16    →    -4/20 ∙ 16/-9

Step 2:  Reduce any fractions if necessary, it makes multiplying them easier and you will have to reduce anyway at the end.  It’s easier arithmetic to reduce at this step.  The first fraction reduces because both the numerator and denominator are divisible by 4.  

-1/5  ∙   16/-9    

Step 3:  Multiply numerators and denominators together to get one fraction

(-16)/(-45)  

Step 4:  Cancel out the negatives, a negative divided by a negative is a positive.  Our final answer is

 

16/45  


4 0
3 years ago
Can someone please answer. There is one problem. There's a picture. Thank you!!!
djverab [1.8K]
The answer for your question is C. The reason is I multipled 15 and 6 which gave me 90 and that is closest to the answer C which is 72.73. Hope this helps:)
3 0
3 years ago
Which of the following expression expressions is equivalent to cos3x/sinxcosx?
77julia77 [94]
Correct Option:
Option B

Solution:
The given expression is:

\frac{cos(3x)}{sin(x)cos(x)}

cos(3x) can be written as cos(2x +x). Expanding it, we get:

cos(3x) = cos(2x+x) \\  \\ 
cos(3x) =cos(2x)sin(x)-sin(2x)cos(x)

Using this value of cos(3x) in given equation, we get:

\frac{cos(3x)}{sin(x)cos(x)} \\  \\ 
= \frac{cos(2x)sin(x)-sin(2x)cos(x)}{sin(x)cos(x)} \\  \\ 
= \frac{cos(2x)sin(x)}{sin(x)cos(x)}- \frac{sin(2x)cos(x)}{sin(x)cos(x)}  \\  \\ 
= \frac{cos(2x)}{cos(x)} - \frac{sin(2x)}{sin(x)} \\  \\ 
=sec(x)cos(2x)-csc(x)sin(2x)
8 0
3 years ago
Read 2 more answers
Karen currently has an account balance of $7,062.25. She opened the account 17 years ago with a deposit of $2,640.95. If the int
Setler79 [48]
The interest rate is 0.4833333%
5 0
3 years ago
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