Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Answer:
Reflect over the x-axis and shift up 3.
Answer:
A. x = 3.03
B. x = 4/3
Step-by-step explanation:
A. 2000 (x-0.03) = 6000 is quickly simplified byu dividing both sides by 2000:
(x - 0.03) = 3. Removing the parentheses, we get: x = -0.03 = 3, or x = 3.03.
B. The distributive property is the faster method here. We determine that the LCD is 12 and multiply both sides of this equation 1/4 (4+x) = 4/3 by 12:
3(4 + x) = 16
and then carry out the indicated multiplication: 12 + 3x = 16, or
3x = 4, or x = 4/3
The difference of two cubes is factored by
x^3-y^3=(x-y)(x^2+xy+y^2)
In this case it would be
C)
