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topjm [15]
3 years ago
9

Help solve this problem please

Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

5,0

Step-by-step explanation:

you move point b to the right 1 and down 2 to get your new b prime

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ABCD diagonals intersect at E. If m∠BAC=4x+5 and m∠CAD=5x-14, then find m∠CAD.
Travka [436]

Answer: m∠CAD = 81°

Step-by-step explanation: <u>Diagonal</u> is a line that unites opposite sides.

ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.

The figure below shows ABCD with its diagonals.

Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So

m∠BAC = m∠CAD

4x + 5 = 5x - 14

x = 19

Then, m∠CAD is

m∠CAD = 5(19) - 14

m∠CAD = 81

The angle m∠CAD is 81°.

7 0
3 years ago
Please help me?? Solve for x
Delvig [45]
X= 10

This is because 180-95= 85 which would make 8x+5= 85

Subtract 5 from both sides and get 8x=80

Then, divide 8 from both sides and get x=10
3 0
3 years ago
Read 2 more answers
A dogs weighs 7 pounds and triples each year for two years. How much does the dog weigh?
Tanya [424]
Year 1: 7lbs x 3years= 21lbs
Year 2: 21lbs x 3years = 63lbs
5 0
3 years ago
Read 2 more answers
Solve quadratic equation (x-3)^2+5=14
loris [4]
(X-3)^2+5=14
Step 1: simplify both sides of the equation
X^2-6x+14=14

Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0

For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0

Step 3: Use quadratic formula with a=1, b=-6, c=0

The answer is x=6 or x=0

5 0
3 years ago
An equation of the line that passes through (3, 1) and (0, 10).
MrMuchimi

Answer:

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

Step-by-step explanation:

(3, 1) and (0, 10)

m=y²-y¹/x²-x¹

m=10-1/0-3

m=9/-3

m=-3

y=mx+b

y-y=m(x-x1)

y-1=-3(x-3)

y-1=-3x+9

+1 +1

y=-3x+10

3 0
3 years ago
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