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3 years ago

Help solve this problem please

Mathematics

1 answer:

eimsori [14]3 years ago

7 0

Answer:

5,0

Step-by-step explanation:

you move point b to the right 1 and down 2 to get your new b prime

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the zero-product property and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the second equation and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

Solve the inequality (x + 4)(x - 1) < 0.

Rzqust [24]

Answer: −4<x<1

Step-by-step explanation: plz mark brainliest

8 0

4 years ago

What is 5m2- 15m- 200

vitfil [10]

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40

1 40

2 20

4 10

5 8

Based on the middle term we know that 5 and 8 are our best option.

5(m 5) (m 8)

We know the signs have to be one + and one - because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

3 0

3 years ago

Solve for the system of liner equations by substitution. X+4y= -1 -3x-14=y

dem82 [27]

X=12x+55
y=-3x-14
simplfy to the right side

6 0

4 years ago

The diameter of a circle is 14 in. Find its area in terms of

Luda [366]

Answer:

Given - Diameter of circle = 14 in

To find - Area of circle

Solution -

Diameter= 2 × Radius

14 = 2 × R

14/2 = R

7 = R

Area of circle= π r^²

22/7 × 7 × 7

22 × 7

154

7 0

3 years ago