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aleksklad [387]
2 years ago
11

3 time the sum of a number and 5 ​

Mathematics
2 answers:
ira [324]2 years ago
4 0
The equation would be 3(x + 5)
lawyer [7]2 years ago
3 0

Answer:

3(x+5) is the answer.

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The sum of the measures of the interior angles of a quadrilateral is 360°. If the acute interior angle of the figure measures 75
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The sum of the interior angles of a quadrilateral is 4 Right Angles or 360 Degrees.

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Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,
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I'll abbreviate the definite integral with the notation,

I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx

We're given

  • I(f,1,8)=9
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Recall that the definite integral is additive on the interval [a,b], meaning for some c\in[a,b] we have

I(f,a,b)=I(f,a,c)+I(f,c,b)

The definite integral is also linear in the sense that

I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)

for some constant scalars k,\ell.

Also, if a\ge b, then

I(f,a,b)=-I(f,b,a)

a. I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}

b. I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}

c. I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}

d. I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}

e. I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}

f. I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}

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