Can you answer this one for my plz I need before Monday ty
1 answer:
Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5
The vertex is (-2, 5).
The axis of symmetry is x = -2.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5
The vertex is (-2, 5).
The axis of symmetry is x = -2.
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Answer:
1
Step-by-step explanation:
We have the graph of f(x).
In order to find f(0), we simply need to find the y-coordinate of the coordinate when x is 0.
From the graph, we can see that there is a point at (0,1).
In other words, when x is 0, f(x) is 1.
Therefore: