Question

For 9 and 9A, find the slope of the line​

Answer 1

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$ and $(x_ {2}, y_ {2})$ are two points through which the line passes.

Question 1:

According to the image, we have the following points:

$(x_ {1}, y_ {1}) :( 2, -6)\\(x_ {2}, y_ {2}): (- 6,5)$

Substituting we have:

$m = \frac {5 - (- 6)} {- 6-2} = \frac {5 + 6} {- 8} = \frac {11} {- 8} = - \frac {11} {8}$

Thus, the slope is: $- \frac {11} {8}$

Question 2:

According to the image, the line goes through the following points:

$(x_ {1}, y_ {1}): (- 1,2)\\(x_ {2}, y_ {2}) :( 2, -2)$

Substituting we have:

$m = \frac {-2-2} {2 - (- 1)} = \frac {-4} {2 + 1} = \frac {-4} {3} = - \frac {4} {3}$

Thus, the slope is: $- \frac {4} {3}$

Answer:

Slope 1: $- \frac {11} {8}$

Slope 2:$- \frac {4} {3}$