In triangle ABC,
AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x) tan30 <span>=(24−x)/</span><span>√3
</span>
In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
x1 = x2 =6
AD = AC - DC = 24- (24-x) = 6</span></span>
The greatest whole possible whole number length of the unknown side is 9 inches.
<h3>How to identify if a triangle is acute?</h3>
Let us have:
H = biggest side of the triangle
And let we get A and B as rest of the two sides.
Then we get:
If
then the triangle is acute
Two sides of an acute triangle measure as 5 inches and 8 inches
The length of the longest side is unknown.
We have to find the length of the unknown side
WE know that the longest side of any triangle is a hypotenuse
For an acute triangle we know:
Here in this sum,
a = 5 inches
b = 8 inches
c = ?
Substituting we get,
c < 9
Hence, The greatest whole possible whole number length of the unknown side is 9 inches.
Learn more about angles;
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Answer:
78 tickets left to be sold
Step-by-step explanation:
87-9=78
Answer:
1.
Step-by-step explanation:
1. sin 241 = sin(61 + π) = -sin61 = -t^(1/2)
2. sin^2 + cos^2 =1, cos 61= (1-t)^(1/2)
3. [2sin^2 (x)sin(x) +2cos^2 (x)sin(x)]/2cos(x) = 2sin(x) / 2cos(x) = tan(x)
4. tan (x), x do not equal to （π/2 +or- kπ）
x do not equal to 90，270。
Answer:54
Step-by-step explanation:
Pentagon has 5 sides
n=5
Sum of interior angles=180(n-2)
Sum of interior angles=180(5-2)
Sum of interior angles=180x3
Sum of interior angles=540
Size of each interior angle =540/n
Size of each interior angle =540/5
Size of each interior angle=108
x=108/2
x=54
