Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
11
Step-by-step explanation:
Constant of proportionality, k, is the ratio of the quantity of variable y to the quantity of variable x.
Using a point on the line, (4, 44),
Constant of proportionality, k = 
.
Constant of proportionality of the graph is 11.
Answer:
the 2.5 cup
Step-by-step explanation:
0.89÷2=0.445
1.10÷2.5=0.44
1.75÷3.5=0.5
Answer:
A
Step-by-step explanation:
- 
(x + 3) > x - 3 ( multiply both sides by 2 to clear the fraction )
- (x + 3) > 2x - 6 ← distribute parenthesis on left side by - 1
- x - 3 > 2x - 6 ( subtract 2x from both sides )
- 3x - 3 > - 6 ( add 3 to both sides )
- 3x > - 3
divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity
x < 1
B
hope this helps :)
(can you please mark me as brainliest?)
