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worty [1.4K]
3 years ago
8

Write an equation for the line that passes through the two points: (4,3), (6, -3)

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

y= -3x+15.

Step-by-step explanation:

To solve this equation, we first need to calculate the slope of the equation:

m= \frac{-3-3}{6-4} m= \frac{-6}{2} m= -3.

Now, we can simply plug in our slope value into our line equation (y= mx+b) with one of the point listed to find our b value.

3= -3(4)+b

3= -12+b

15=b

Finally, the equation we get is:

y= -3x+15

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Rhombus LMNO is shown with its diagonals. Rhombus L M N O is shown. Diagonals are drawn from point M to point O and from point L
LUCKY_DIMON [66]

In a Rhombus the diagonals intersect and divides it in two equal halves.

Therefore LP = 28/2

LP = 14cm

Answered by GauthMath if you like please click thanks and comment thanks

3 0
3 years ago
Points A, B, and C are collinear. Point B is between A and C. Solve for x if AC = 3x + 3, BC = 3, and AB = 2x + 2.
Ksenya-84 [330]

Answer:

x=2.

Step-by-step explanation:

It is given that points A, B, and C are collinear. Point B is between A and C.

Using segment addition property, we get

AC=AB+BC

It is given that AC = 3x + 3, BC = 3, and AB = 2x + 2.

3x+3=(2x+2)+3

3x+3=2x+5

Isolate variable terms.

3x-2x=5-3

x=2

Therefore, the value of x is 2.

5 0
3 years ago
7. Evaluate 4P2<br><br> O<br><br> 22<br><br> O<br><br> 12<br><br> O<br><br> 14<br><br> 5
Reika [66]

Answer:

<h2>12</h2>

Step-by-step explanation:

To evaluate 4P2, we will use the permutation formula as shown;

nPr = \frac{n!}{(n-r)!}

4P2 = \frac{4!}{(4-2!}

= \frac{4!}{2!} \\= \frac{4*3*2!}{2!}\\ = 4*3\\= 12

4P2 = 12

5 0
4 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p: n = 195,
Troyanec [42]

Answer:

c. 0.778 < p < 0.883.

Step-by-step explanation:

The formula for confidence interval for proportion =

p ± z score × √p(1 - p)/n

p = x/n

n = 195, x = 162

z score for 95% confidence Interval = 1.96

p = 162/195

p = 0.8307692308

p ≈ approximately equal to = 0.8308

0.8308 ± 1.96 × √0.8308 × (1 - 0.8308)/195

0.8308 ± 1.96 ×√0.8308 × 0.1692/195

0.8308 ± 1.96 × √0.0007208788

0.8308 ± 1.96 × 0.0268491862

0.8308 ± 0.052624405

Confidence Interval

= 0.8308 - 0.052624405

= 0.778175595

Approximately = 0.778

= 0.8308 + 0.052624405

= 0.883424405

Approximately = p

0.883

Therefore, the confidence interval for this proportion = (0.778, 0.883) or option c. 0.778 < p < 0.883

6 0
3 years ago
How many fluid ounces are in 3 quarts and 2 cups ?
sasho [114]
15 fluid ounces.
1quart= 4 cups

8 0
3 years ago
Read 2 more answers
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