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3 years ago

9

Fred bought 1.75 liters more laundry detergent than bleach (True or False)

1 answer:

sammy [17]3 years ago

4 0

False because we dont know that because you didnt give us the problem'

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Cathrine was concerned about her report card grade. She had 5 tests the whole semester. If her scores on each test were 93, 82,

enyata [817]

Answer:

81.6

Step-by-step explanation:

mean/average of her grade = sum of all scores/the number of scores

= (93+82+74+92+67)/5

= 81.6

4 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

3 years ago

Best Buy is having a sale. iPads are marked down 20%. Of the original cost is $399, how much will you pay?

iren [92.7K]

It is

$79.80 I believe
According to me?

5 0

3 years ago

Read 2 more answers

Dividing with decimals

horrorfan [7]

Here's an example: I hope this helps you out

4 0

3 years ago

Given: Circle k(O) Diameter <br><br>XY tangent WZ, XY = 10, and WZ = 12 .Find: YZ

PtichkaEL [24]

Answer:

<h2>Side YZ is 8 units long.</h2>

Step-by-step explanation:

We can deduct form the graph that segment WO is a radius of the circle and XY is its diameters.

By given, we know that $XY = 10$ , which means $WO=\frac{XY}{2}=\frac{10}{2}=5$ , by radius definition.

An important characteristic of tangents about circles is that the tangent is always is perpendicular to the radius, that means $\angle OWZ = 90\°\\$ and $\triangle OWZ$ is a right triangle, that means we can use Pythagorean's Theorem to find the side YZ.

$OZ^{2} =WZ^{2}+OW^{2}$

Where $OZ$ is the hypothenuse and $WZ$ , $OW$ are legs of the triangle.

Replacing all given values, we have

$OZ^{2}=12^{2}+5^{2}\\OZ=\sqrt{144+25}=\sqrt{169}\\ OZ=13$

However, by sum of segments, we have

$OZ=OY+YZ$ , where $OY=OW=5$ and $OZ=13$

$13=5+YZ\\YZ=13-5\\YZ=8$

Therefore, side YZ is 8 units long.

3 0

3 years ago