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bearhunter [10]
3 years ago
13

What is 78 ÷ 5 and the remainder

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:

The answer is: (15) and the remainder is (6)

~i really hope this helps, have a gr8 day my friend!~

Step-by-step explanation:

dybincka [34]3 years ago
4 0

Answer:

Step 1) Start by dividing 78 by 5 to get the decimal answer as illustrated below. Note that we round the answer if necessary, but don't worry, the final answer will still be exact.

78 / 5 = 15.60

Step 2) Next we take the Whole part of the answer in Step 1 and multiply it by the Divisor. As you can see, it does not matter if we rounded in the previous step because the Decimal part is ignored. Furthermore, the Divisor in 78 divided by 5 is 5. Thus, the Whole multiplied by the Divisor is:

15 x 5 = 75

Step 3) Finally, we will subtract the answer in Step 2 from the Dividend to get the answer. The Dividend in 78 divided by 5 is 78. Thus, our final calculation to get the answer is:

78 - 75 = 3

That is all there is to it! Again, the answer is 3.

So here

78 ÷ 5 is 15.6 and it's remainder is 3

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Anyone know #3 for me I’m stuck
steposvetlana [31]
<h3>Answers:  4,  3,  2</h3>

Each number gets its own box, and the values are entered in that exact order.

============================================================

Explanation:

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If we replace x with -1, then we get

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y = -(x)+3

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This means that x = -1 leads to y = 4. So we'll write 4 underneath the "-1" in the y row.

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Similarly, if x = 0, then

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Leading to 3 being the next item we input.

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Finally, if x = 1, we get this y value

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Which is the last value in the bottom row.

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The order of the y values in the bottom row is therefore: 4,  3,  2

This means the points (-1, 4), (0, 3), and (1, 2) are on the line y = -x+3.

Side note: The equation y = -x+3 has slope -1 and y intercept 3.

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Read 2 more answers
Suppose the expected tensile strength of type-A steel is 103 ksi and the standard deviation of tensile strength is 7 ksi. For ty
ExtremeBDS [4]

Answer:

a

i So  the approximate distribution of \= X is \mu_{\= X} =103 and  \sigma_{\= X} = 0.783

ii So the approximate distribution of \= Y is \mu_{\= Y} =105 and  \sigma_{\= Y} = 0.645

b

 the approximate distribution of  \=X  - \= Y is E (\= X - \= Y)  = -2 and  \sigma_{\= X  - \=Y}=1.029

Here we can see that the mean of the approximate distribution is negative which tell us that this negative value of the  data for  \=X  - \= Y sample   are more and their frequency occurrence is higher than the positive values  

c

the value of  P(-1 \le \=X - \= Y  \le 1) is = -0.1639    

Step-by-step explanation:

From the question we are given that

       The expected tensile strength of the type A steel is  \mu_A = 103 ksi

        The standard deviation of type A steel is  \sigma_A = 7ksi

         The expected tensile strength of the type B steel is \mu_B = 105\ ksi

            The standard deviation of type B steel is  \sigma_B = 5 \ ksi

Also the assumptions are

       Let \= X be the sample average tensile strength of a random sample of 80 type-A specimens

Here n_a =80

      Let \= Y be  the sample average tensile strength of a random sample of 60 type-B specimens.

  Here n_b = 60

Let the sampling distribution of the mean be

             \mu _ {\= X} = \mu

                   =103

 Let the sampling distribution of the standard deviation be

               \sigma _{\= X} = \frac{\sigma }{\sqrt{n_a} }

                     = \frac{7}{\sqrt{80} }

                    =0.783

So What this mean is that the approximate distribution of \= X is \mu_{\= X} =103 and  \sigma_{\= X} = 0.783

For \= Y

 The sampling distribution of the sample mean is

               \mu_{\= Y} = \mu

                    = 105

  The sampling distribution of the standard deviation is

               \sigma _{\= Y} = \frac{\sigma }{\sqrt{n_b} }

                    = \frac{5}{\sqrt{60} }

                    = 0.645

So What this mean is that the approximate distribution of \= Y is \mu_{\= Y} =105 and  \sigma_{\= Y} = 0.645                      

Now to obtain the approximate distribution for \=X  - \= Y

               E (\= X - \= Y) = E (\= X) - E(\= Y)

                                =  \mu_{\= X} - \mu_{\= Y}

                                = 103 -105

                                = -2

The standard deviation of \=X  - \= Y is

               \sigma_{\= X  - \=Y} = \sqrt{\sigma_{\= X}^2 - \sigma_{\= Y}^2}

                         = \sqrt{(0.783)^2 + (0.645)^2}

                         =1.029

Now to find the value of  P(-1 \le \=X - \= Y  \le 1)

  Let us assume that F = \= X - \= Y

    P(-1 \le F \le 1) = P [\frac{-1 -E (F)}{\sigma_F} \le Z \le  \frac{1-E(F)}{\sigma_F} ]

                             = P[\frac{-1-(-2)}{1.029}  \le  Z \le  \frac{1-(-2)}{1.029} ]

                             =  P[0.972 \le Z \le 2.95]

                             = P(Z \le 0.972) - P(Z \le 2.95)

Using the z-table to obtain their z-score

                             = 0.8345 - 0.9984

                             = -0.1639

                   

3 0
3 years ago
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