Answer:
3) ![y=\dfrac35x+\dfrac25](https://tex.z-dn.net/?f=y%3D%5Cdfrac35x%2B%5Cdfrac25)
4) a) ![y=-2x+7](https://tex.z-dn.net/?f=y%3D-2x%2B7)
b) ![y=\dfrac12x+\dfrac92](https://tex.z-dn.net/?f=y%3D%5Cdfrac12x%2B%5Cdfrac92)
Step-by-step explanation:
<u>Exercise 3</u>
![-3x + 5y = 2](https://tex.z-dn.net/?f=-3x%20%2B%205y%20%3D%202)
![\implies 5y = 3x + 2](https://tex.z-dn.net/?f=%5Cimplies%205y%20%3D%203x%20%2B%202)
![\implies y=\dfrac35x+\dfrac25](https://tex.z-dn.net/?f=%5Cimplies%20y%3D%5Cdfrac35x%2B%5Cdfrac25)
<u>Exercise 4</u>
a) If L2 is parallel to L1, it has the same slope (gradient) ⇒ ![m = -2](https://tex.z-dn.net/?f=m%20%3D%20-2)
If L2 passes through point (3, 1):
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
![\implies y-1=-2(x-3)](https://tex.z-dn.net/?f=%5Cimplies%20y-1%3D-2%28x-3%29)
![\implies y=-2x+7](https://tex.z-dn.net/?f=%5Cimplies%20y%3D-2x%2B7)
So L2 = L1
b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1 ⇒ ![m = \dfrac12](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac12)
If L3 passes through point (-5, 2):
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
![\implies y-2=\dfrac12(x+5)](https://tex.z-dn.net/?f=%5Cimplies%20y-2%3D%5Cdfrac12%28x%2B5%29)
![\implies y=\dfrac12x+\dfrac92](https://tex.z-dn.net/?f=%5Cimplies%20y%3D%5Cdfrac12x%2B%5Cdfrac92)
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
Answer:
This is the equation for cellular respiration.
Step-by-step explanation:
C6H1206 is glucose. O2 is oxygen. They react to produce 6H20, which is water, and 6CO2, which is carbon dioxide. Energy is also produced which is represented by 2800 kJ. Energy is created in the form of ATP and heat.
No i don't but if u need anything else about this syndrome feel free to ask
Answer: as long as w x and x y have opposite reciprocals for their slopes they are perpendicular
Step-by-step explanation: