Answer:
10980 is the correct answer
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Smallest side XYZ/ Smallest side ABC = Longest side XYZ/ Longest side ABC
Let longest side XYZ be x
280/112 = x/144
x = (280/112)×144
x = 360
Option D will be your answer
Hope it helped!
Answer:
2 different perimeters, 32 cm and 40 cm
Step-by-step explanation:
Given the area of a rectangle is 64 cm squared.
We know, Area of the rectangle is = length x breath
∴ 64 = 8 x 8
Hence the sides can be 8 cm by 8 cm.
So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm
= 32 cm
Also, Area of the rectangle is = length x breath
∴ 64 = 16 x 4
So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm
= 40 cm
