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3 years ago

Simplify. 14+4(12−34)2 Enter your answer in the box.

Mathematics

2 answers:

Allushta [10]3 years ago

7 0

Answer:1/4+4(1/2−3/4)^2

Step-by-step explanation Its supposed to be a fraction but when you copy and paste it won't allow it to be fraction. Answer is 1/2

Komok [63]3 years ago

5 0

14 + 8(12-34)

14 + 8(-22)
14 - 176

- 162 is your answer

hope this helps

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The vertex of this parabola is at (-3, 6). Which of the following could be its equation?

12345 [234]

Nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex

therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6

A is ansre

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3 years ago

Read 2 more answers

Please help me out with this problem!

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.

Given y = f(x) then f(x + a) is a horizontal translation of a units

• If a > 0 then shift to the left of a units

• If a < 0 then shift to the right of a units

Here shift to the right of 1 unit, thus

y = f(x - 1)

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

Note the y- coordinates are the negative of each other, thus

- y = f(x)

Now $\frac{y}{-1}$ = - y, hence

The equation for the red graph is

$\frac{y}{-1}$ = f(x - 1) → C

6 0

3 years ago

The functions r and s are defined as follows.

irina1246 [14]

Answer:

r(s(-2)) = -2

Step-by-step explanation:

We are given these following functions:

$r(x) = -2x + 2$

$s(x) = x^2 - 2$

Find the value of r(s (-2)).

First we find the composition of r and s functions. It is:

$r(s(x)) = r(x^2-2) = -2(x^2-2) + 2 = -2x^2 + 6$

At x = -2

$r(s(-2)) = -2(-2)^2 + 6 = -8 + 6 = -2$

r(s(-2)) = -2

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3 years ago

The quadrilateral shown is a parallelogram. What is the measure of DC?

Schach [20]

Answer:

B) 12

Step-by-step explanation:

Opposite sides are congruent

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3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

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3 years ago