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Flura [38]
2 years ago
5

Simplify. 14+4(12−34)2 Enter your answer in the box.

Mathematics
2 answers:
Allushta [10]2 years ago
7 0

Answer:1/4+4(1/2−3/4)^2

Step-by-step explanation Its supposed to be a fraction but when you copy and paste it won't allow it to be fraction. Answer is 1/2

Komok [63]2 years ago
5 0
14 + 8(12-34)

14 + 8(-22)
14 - 176

- 162 is your answer

hope this helps
You might be interested in
11 more than four times a number is 39
Aliun [14]

Hello!

Your answer is: 7

(X = "<em>A number</em>")

<em>"11 more than four times a number is 39"</em> in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

4 0
3 years ago
36= -12y<br><br> This is here to fill the 20 characters
marin [14]
The answer is y=-3

This is here for the 20 characters 
3 0
2 years ago
Read 2 more answers
Can anyone answer this please i need to be for sure I’m right
Genrish500 [490]
The answer to this question is B, (-infinity, -28]. 

We can get this answer by first multiplying each side of the inequality by 7. That would get rid of the fraction. When one does that, the result is d + 28 \leq 0. That means that d \leq -28. In interval notation, which is the notation the problem is asking us, that would be (-infinity, -28], since d is all values less than -28 this includes infinity, but it also includes -28, so there is a ] around it. That means that the answer to this question is B, (-infinity, -28]. 
7 0
3 years ago
Pls help !!<br><br> Solve and CHECK.<br><br> 1 / 4 ( p - 7) = 1/6 ( p - 3)
victus00 [196]

Answer:

the answer would be p= 15

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

\lim_{x\to 3}(x^2+8x-2)=33-2

\lim_{x\to 3}(x^2+8x-2)=31

Therefore, the correct option is D.

4 0
3 years ago
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