Answer:1
Step-by-step explanation:
they have no other common factors
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula
to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer:
.
<span>the tens digit = n
</span><span>the units digit = n-5
n + n-5 = 9
2n = 9+5
2n = 14
n = 7 </span>← the tens digit
the units digit = n-5 = 7 - 5 = 2
<span>the number is 72</span>
The expression equivalent to 4^-5 • 3^-5 is 12^-5
<h3>What are equivalent expressions?</h3>
Equivalent expressions are simply known as expressions with the same solution but different arrangement.
Given the index expressions;
4^-5 • 3^-5
Using the exponent rule, the two values are have different bases but the same exponent and thus, we multiply the bases and leave the exponents the same way.
This can be written as;
4(3) ^ -5
expand the bracket
12^-5
Thus, the expression equivalent to 4^-5 • 3^-5 is 12^-5
Learn more about equivalent expressions here:
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Plot each point on a graph , then count how many you need to go up and then over in this case it is 8 over 1 then calculate the y int so y= 8x -25