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3 years ago

5

Your sister is starting 9th grade next year and is thinking about going to college. What step would you recommend she take first

?

2 answers:

dexar [7]3 years ago

7 0

Take a placement test and she if the college she want to go to will take someone her age usually Tech school have some programs that will take people at 16 but some might not.

stiks02 [169]3 years ago

4 0

Have her score high on standardized tests, research interests, figure out transportation/accommodation once she leaves HS.

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A large rock has a mass of 9,000 grams. What is the mass of the rock in kilograms ?

katovenus [111]

The mass of the rock in kg is 90,000 kg

4 0

2 years ago

Read 2 more answers

(10 POINTS AND BRAINLIEST FOR BEST)

Naddik [55]

Answer:

C. II only

Step-by-step explanation:

Basically all you need do is plug these answers in and if the complete the inequality to make a true statement.

Yes i know no body want to do that but that whats need to be done lol.

once i plug 7 12/7+8 = 12.83

12.83>20

is incorrect

so we need continue

7*2.5+8>20

7*2.5= 17.5

17.5+8= 25.5

25.5>20

this a true statement

so we know 2.5 is an answer

now we need plug in -3

7*-3= -21

-21 +8 = -13

-13>20

this is incorrect

6 0

3 years ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

In questions 1a-1d, choose yes or no to tell if the number 1/2 will make each equation true.

Tresset [83]

Answer:

Step-by-step explanation:

1a = yes

1b = no, you don’t add the denominators together when adding.

1c = yes

1d = yes

4 0

2 years ago

Given the system of equations presented here:

Bumek [7]

ANSWER

The correct answer is option B

EXPLANATION

The equations are

$3x+5y=29---(1)$

and

$x+4y=16---(2)$

When we multiply the second equation by $-3$ , we obtain;

$-3x-12y=-48---(3)$

When we combine this new equation with equation (1).

$-7y=-19$

We can see that $x$ has been eliminated from the equation.

We can then, solve for $y$ and then substitute the result in to any of the equations to find $x$ .

Hence the correct answer is option B

8 0

2 years ago

Read 2 more answers