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Elanso [62]
3 years ago
6

Annabelle earn $72 she gives her mother one-third of his amount and spent 1/4 of the money on going out. what fraction of the $7

2 is left​
Mathematics
2 answers:
Katarina [22]3 years ago
4 0

First, let's find one-third of the money that she gives to her mother.

72 / 3 = $24

Second, find one-fourth of the money she spends on going out.

72 / 4 = $18

Fourth, add.

24 + 18 = $42 spent.

Now she has $30 left of the original $72. Put this into a fraction;

30/72 → 5/12

Annabelle has 5/12 ($30) of the money left.

Best of Luck!

mariarad [96]3 years ago
3 0

Answer:

5/12

Step-by-step explanation:

She spent 1/3=4/12 and 1/4=3/12. In total 4/12 + 3/12=7/12. Now subtract 7/12 from the total: 12/12 - 7/12=5/12.

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Y = -2x in standard form
7nadin3 [17]
The answer would be 2x+y=0

Hope this helps

Have a great day/night

Feel free to ask any questions
4 0
3 years ago
Read 2 more answers
Kelly has 236 feet of fence to use to enclose a rectangular space for her dog. She wants the width to be 23 feet. Select the cor
Setler [38]

Answer:

Length = x feet = 95 feet

Step-by-step explanation:

The labeled triangles are not included in the question, therefore, I will calculate the length of the rectangular space for Kelly's dog

Perimeter of a rectangle = 2(length + width)

Perimeter of a rectangle = 236 feet

Width = 23 feet

Length = x feet

Perimeter of a rectangle = 2(length + width)

236 = 2(x + 23)

236 = 2x + 46

236 - 46 = 2x

190 = 2x

x = 190/2

x = 95 feet

Length = x feet = 95 feet

7 0
3 years ago
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
3 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
Express 72 as a product of its prime factors.
ASHA 777 [7]
The trick is to just keep factoring out 2 until you get all prime numbers.

72 = 36 * 2
36 = 18 * 2
18 = 9 * 2
9 = 3 * 3

Therefore, the answer is:
72 = 2 * 2 * 2 * 3 * 3

Hope this helps
3 0
3 years ago
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